SSCP: Get diagonality (bartlett)...

Tests the hypothesis that the selected SSCP matrix object is diagonal.

## Setting

Number of constraints
  modifies the number of independent observations. The default value is 1.

## Algorithm

The test statistic is |R|N/2, the N/2-th power of the determinant of the correlation matrix. Bartlett (1954) developed the following approximation to the limiting distribution:

χ2 = -(N - numberOfConstraints - (2p + 5) /6) ln |R|

In the formulas above, p is the dimension of the correlation matrix, N-numberOfConstraints is the number of independent observations. Normally numberOfConstraints would equal 1, however, if the matrix has been computed in some other way, e.g., from within-group sums of squares and cross-products of k independent groups, numberOfConstraints would equal k.

We return the probability α as

α = chiSquareQ (χ2 , p(p-1)/2).

A very low α indicates that it is very improbable that the matrix is diagonal.

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- What was new in 4.1?